Your birthday can be anything without conflict, so there are 365 choices out of 365 for your birthday. Example: Inside a bag there are 3 green balls, 2 red balls and and 4 yellow balls. Let’s imagine that you are one of these three people. Stack Exchange network consists of 176 Q&A communities including Stack Overflow, the largest, most trusted online community for developers to learn, share … (b) What is the probability that none of the patients will be cured? Also the two cards are picker without replacement. The answer he gave is .226 but I keep getting .214 or something like that. A box contains five balls; three red and two green. Two balls are randomly drawn without replacement. The OR of Two Events In a sample of 1000 people, 120 are left handed. ... Probability of getting "at least one" white is the probability of each scenario added together. Sampling without Replacement When sampling is done without replacement, each member of a population may be chosen only once. (a) What is the probability that all three balls are white? Imagine drawing the cards one by one. When 3 balls are picked with replacement the probability of getting at least one green is 1-(the probability of getting 3 reds) Because the probability is the same every time the chance of getting 3 reds is $0.6^3=0.216$ (or in fractions $(\frac{3}{5})^3 = \frac{27}{125}$). (b) What is the probability that exactly one ball is white? question 6. Find the probability that neither of the cards is a heart. For the first card, the chance of drawing a king is [math]\frac{4}{52}=\frac{1}{13}. P(at least one) = 1 – P(none) We will start, then, by computing the probability that there is no shared birthday. Three balls are drawn, without replacement, from the bag. How To Use A Probability Tree Diagram To Calculate Probabilities Of Two Events Which Are Dependent? (c) What is the probability that at least one patient will be cured? The probability of getting Sam is 0.6, so the probability of Alex must be 0.4 (together the probability is 1) Now, if you get Sam, there is 0.5 probability of being Goalie (and 0.5 of not being Goalie): If you get Alex, there is 0.3 probability of being Goalie (and 0.7 not): Two unrelated people are selected at random without replacement. So then the probability of at least 1 Heart is, Find the probability that at least one of the two people is left-handed. Event A: A red ball is drawn from a box without replacement. so the probability of getting at least one king is 1 - 0.7187 = 0.2813 to 4 d.p.. Edit: You would expect a slightly higher probability without replacement, since you are improving your odds of getting a king for the first time on each draw as Are events A and B best described as independent events or dependent events? --- I missed class the day my professor went over this problem and for the life of me I cannot get the answer my professor gave us. 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