# sodium carbonate + hydrochloric acid

2. Thus, it will not be present in the net ionic equation and are spectator ions. Write and balance the chemical equation and then calculate; "how many moles of HCl are required to react with 0.050 moles of sodium carbonate?" The carbonic acid rapidly breaks down to give carbon dioxide and water, leaving the solution neutral. Remember, strong bases can be just as toxic and corrosive as strong acids. ( Acid + Base -> Salt + Water ). Hydrochloric acid is acidic, meaning that it releases protons (H⁺) when dissolved in water. Transfer a 25cm 3 aliquot (portion) of your sodium carbonate solution to a 250cm3 capacity conical flask. Titrate with the hydrochloric acid. your standard sodium carbonate solution dilute hydrochloric acid to standardise phenolphthalein indicator solution methyl orange indicator solution Methods 1. The reaction is as follows - NaHCO3(aq) + HCl(aq) -> NaCl(aq) + H2O(l) + CO2(g) This is an example of a neutralization reaction. Sodium carbonate (Na2CO3) reacts with hydrochloric acid (HCl) to give sodium chloride (NaCl) and carbonic acid (H2CO3). Add a few drops of phenolphthalein indicator solution. That’s precisely it. The products formed are - NaCl(Sodium Chloride), Water and Carbon-dioxide. Sodium carbonate is a basic compound, meaning that it generates hydroxide ions (OH⁻) when dissolved in water. Imagine this, if you added too much NaOH to the acid, then the resulting solution would become strongly basic. The chemical equation for the reaction of sodium carbonate and hydrochloric acid is given as: Ionic form of the above equation follows: As, sodium and chloride ions are present on both the sides of the reaction. When combined, aqueous solutions of sodium carbonate and hydrochloric acid generate an acid-base reaction. Sodium carbonate and Hydrochloric acid, after a reaction, give Sodium chloride, Water, and Carbon dioxide as products. 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