# why is 1^infinity indeterminate

In both cases the fraction involving n becomes infinitely small and the power becomes infinitely big, which means they are both of the form 1∞. The second you put an equals sign down and arrive at an answer, you are no longer doing 1∞ its now 1x which IS determinate. By signing up, you'll get thousands of step-by-step solutions to your homework questions. or an INDETERMINATE that which cannot be determined. But they evaluate to different numbers. u/Polarexpressos. This is what 'infinity' is, and notions of 'unbounded quantities' need to be avoided for rigor, even though they may be conceptually understandable. Close. saying that 0 • ∞ is indeterminate means that one cannot adjoin ∞ to the real numbers and get a system with well-defined notions of addition and multiplication. Then (x→1, y→∞)lim x^y = (y→∞)lim x^y (because as y→∞, x will necessarily approach 1, so that condition is redundant), and (y→∞)lim x^y = (y→∞)lim (1+z/y)^y = e^z. 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